Nitha Mulungu
May 25
What is the apparent weight of a 50kg person in a lift that is acceleration downwards at 1.5m/s^2?
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ChatGPT
May 25
The apparent weight of a person in an elevator is equal to the normal force acting on them.
The normal force can be calculated using the equation:
Normal force = mass x (acceleration due to gravity + acceleration of the elevator)
Normal force = 50kg x (9.81m/s^2 + 1.5m/s^2)
Normal force = 50kg x 11.31m/s^2
Normal force = 565.5 N
Therefore, the apparent weight of a 50kg person in a lift that is accelerating downwards at 1.5m/s^2 is 565.5 N.
The normal force can be calculated using the equation:
Normal force = mass x (acceleration due to gravity + acceleration of the elevator)
Normal force = 50kg x (9.81m/s^2 + 1.5m/s^2)
Normal force = 50kg x 11.31m/s^2
Normal force = 565.5 N
Therefore, the apparent weight of a 50kg person in a lift that is accelerating downwards at 1.5m/s^2 is 565.5 N.
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Google Gemini AI
May 25
Apparent weight = Actual weight - Buoyant force (for objects inside a liquid or gas) + Inertial force
Given,
Actual weight = 50 kg × 9.8 m/s^2 = 490 N
Acceleration downwards = 1.5 m/s^2
Inertial force = mass × acceleration = 50 kg × (-1.5 m/s^2) = -75 N
Apparent weight = 490 N + (-75 N) = 415 N
Therefore, the apparent weight of the person is 415 N.
Given,
Actual weight = 50 kg × 9.8 m/s^2 = 490 N
Acceleration downwards = 1.5 m/s^2
Inertial force = mass × acceleration = 50 kg × (-1.5 m/s^2) = -75 N
Apparent weight = 490 N + (-75 N) = 415 N
Therefore, the apparent weight of the person is 415 N.
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Anonymous
May 26
Structure of furan
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Oywek Denis
May 26
Furan
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