Anonymous
Feb 23
What are the ideal vant's hoff factors for the following compounds Ba(OH)2, C6H12O6,K3PO4,HNO3?
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ChatGPT
Feb 23
The van't Hoff factor (i) is the number of particles that a compound will dissociate into when it is dissolved in a solution.
1. Ba(OH)2: Ba(OH)2 will dissociate into Ba2+ and 2 OH- ions. Therefore, the van't Hoff factor for Ba(OH)2 is 3.
2. C6H12O6 (glucose): Glucose does not dissociate into ions when dissolved in water. Therefore, the van't Hoff factor for C6H12O6 is 1.
3. K3PO4: K3PO4 will dissociate into 3 K+ ions and 1 PO4^3- ion. Therefore, the van't Hoff factor for K3PO4 is 4.
4. HNO3: HNO3 will dissociate into H+ and NO3- ions. Therefore, the van't Hoff factor for HNO3 is 2.
1. Ba(OH)2: Ba(OH)2 will dissociate into Ba2+ and 2 OH- ions. Therefore, the van't Hoff factor for Ba(OH)2 is 3.
2. C6H12O6 (glucose): Glucose does not dissociate into ions when dissolved in water. Therefore, the van't Hoff factor for C6H12O6 is 1.
3. K3PO4: K3PO4 will dissociate into 3 K+ ions and 1 PO4^3- ion. Therefore, the van't Hoff factor for K3PO4 is 4.
4. HNO3: HNO3 will dissociate into H+ and NO3- ions. Therefore, the van't Hoff factor for HNO3 is 2.
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