The voltage drop across a transistor network is 12v if the total resistance is 5.6kohms what is the current level (2)what is the power delivered (3)how much energy is dissipated in 1hour?

1) To find the current level, we can use Ohm's Law: V = IR, where V is the voltage drop, I is the current, and R is the total resistance.

Given:
V = 12V
R = 5.6kΩ = 5600Ω

Using Ohm's Law:
12 = I * 5600
I = 12 / 5600
I ≈ 0.00214 A

Therefore, the current level is approximately 0.00214 A.

2) To find the power delivered, we can use the formula: P = IV, where P is power, I is current, and V is voltage.

Given:
I = 0.00214 A
V = 12V

Using the formula:
P = 0.00214 * 12
P ≈ 0.0257 W

Therefore, the power delivered is approximately 0.0257 W.

3) To find the energy dissipated in 1 hour, we can use the formula: E = P * t, where E is energy, P is power, and t is time.

Given:
P = 0.0257 W
t = 1 hour = 3600 seconds

Using the formula:
E = 0.0257 * 3600
E ≈ 92.52 J

Therefore, the energy dissipated in 1 hour is approximately 92.52 Joules.