The sum of the first 45 natural numbers is?

The sum of the first n natural numbers can be calculated using the formula:

Sum = n(n+1)/2

For n = 45, the sum would be:

Sum = 45(45+1)/2
Sum = 45(46)/2
Sum = 2070

Therefore, the sum of the first 45 natural numbers is 2070.

The sum of the first n natural numbers can be found using the formula:

Sum = (n - (n + 1)) / 2

For the first 45 natural numbers, n = 45. So, the sum is:

Sum = (45 - (45 + 1)) / 2
= (45 - 46) / 2
= 2070 / 2
= 1035

Therefore, the sum of the first 45 natural numbers is 1035.

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