Edward Yayi
May 12
The sides of a tractangle are 31.4cm by 28.3cm with what limit does it's perimeter lie?
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ChatGPT
May 12
The perimeter of a triangle is the sum of the lengths of its three sides.
Given that the sides of the triangle are 31.4cm and 28.3cm, the perimeter can be calculated as:
Perimeter = 31.4 + 28.3 + 31.4 = 90.1 cm
Therefore, the perimeter of the triangle lies within the limit of 90.1 cm.
Given that the sides of the triangle are 31.4cm and 28.3cm, the perimeter can be calculated as:
Perimeter = 31.4 + 28.3 + 31.4 = 90.1 cm
Therefore, the perimeter of the triangle lies within the limit of 90.1 cm.
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Google Gemini AI
May 12
The perimeter of a rectangle is given by the formula:
$$P = 2(l + w)$$
where \(l\) is the length and \(w\) is the width.
In this case, the length is 31.4cm and the width is 28.3cm, so the perimeter is:
$$P = 2(31.4cm + 28.3cm) = 119.4cm$$
However, due to measurement errors, the actual perimeter may not be exactly 119.4cm. The limits within which the perimeter may lie can be determined by considering the possible errors in the measurements of the length and width.
Let's assume that the error in each measurement is at most 0.1cm. This means that the actual length may be between 31.3cm and 31.5cm, and the actual width may be between 28.2cm and 28.4cm.
Using the formula for the perimeter, we can determine the minimum and maximum possible values of the perimeter:
- Minimum possible perimeter: \(P = 2(31.3cm + 28.2cm) = 118.0cm\)
- Maximum possible perimeter: \(P = 2(31.5cm + 28.4cm) = 120.8cm\)
Therefore, the perimeter of the rectangle lies within the limits of 118.0cm and 120.8cm, with a maximum possible error of 1.4cm.
$$P = 2(l + w)$$
where \(l\) is the length and \(w\) is the width.
In this case, the length is 31.4cm and the width is 28.3cm, so the perimeter is:
$$P = 2(31.4cm + 28.3cm) = 119.4cm$$
However, due to measurement errors, the actual perimeter may not be exactly 119.4cm. The limits within which the perimeter may lie can be determined by considering the possible errors in the measurements of the length and width.
Let's assume that the error in each measurement is at most 0.1cm. This means that the actual length may be between 31.3cm and 31.5cm, and the actual width may be between 28.2cm and 28.4cm.
Using the formula for the perimeter, we can determine the minimum and maximum possible values of the perimeter:
- Minimum possible perimeter: \(P = 2(31.3cm + 28.2cm) = 118.0cm\)
- Maximum possible perimeter: \(P = 2(31.5cm + 28.4cm) = 120.8cm\)
Therefore, the perimeter of the rectangle lies within the limits of 118.0cm and 120.8cm, with a maximum possible error of 1.4cm.
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