The ratio of annual income of mr.and Mrs Grayson is 4:3 and their annual expenditure is 3:2.if each of them saves TZS 1000000per year find their annual income?

Let's assume that Mr. Grayson's annual income is 4x and Mrs. Grayson's annual income is 3x.

According to the given ratio, their annual expenditure is 3:2. So, Mr. Grayson's annual expenditure is 3y and Mrs. Grayson's annual expenditure is 2y.

We know that each of them saves TZS 1000000 per year. So, Mr. Grayson's savings is 4x - 3y = 1000000 and Mrs. Grayson's savings is 3x - 2y = 1000000.

From the above equations, we can write:
4x - 3y = 1000000 ...(1)
3x - 2y = 1000000 ...(2)

To solve these equations, we can multiply equation (1) by 2 and equation (2) by 3 to eliminate y:
8x - 6y = 2000000 ...(3)
9x - 6y = 3000000 ...(4)

Subtracting equation (3) from equation (4), we get:
9x - 8x = 3000000 - 2000000
x = 1000000

Substituting the value of x in equation (1), we get:
4(1000000) - 3y = 1000000
4000000 - 3y = 1000000
-3y = 1000000 - 4000000
-3y = -3000000
y = -3000000 / -3
y = 1000000

Therefore, Mr. Grayson's annual income is 4x = 4(1000000) = 4000000 TZS.
And Mrs. Grayson's annual income is 3x = 3(1000000) = 3000000 TZS.