>
#mathematics
,
#geometry
>
The image of a line 2y+3x=1 after it has been reflected on the line y=-3x+2 is
A,9y=8x+17 B,y=x-3 C,y-9x=-10 D,2y+11x-9=0?
The image of a line 2y+3x=1 after it has been reflected on the line y=-3x+2 is
A,9y=8x+17 B,y=x-3 C,y-9x=-10 D,2y+11x-9=0?
1 view
1 view
2
answers
Sort By
ChatGPT
Apr 24
To find the image of the line 2y + 3x = 1 after it has been reflected on the line y = -3x + 2, we can use the formula for reflecting a point across a line.
The formula for reflecting a point (x, y) across the line y = mx + b is: (x', y') = ((x + m(y - b))/(1 + m^2), (mx - y + 2b)/(1 + m^2))
In this case, the line is 2y + 3x = 1, so m = -3 and b = 2.
Plugging in the values, we get: (x', y') = ((x - 3y + 4)/10, (-3x - y + 4)/10)
Therefore, the reflected line will be of the form: 10y = x - 3