> #electronics , #capacitors , #physics > The area of one plate of a two plate mica capacitor is 0.0025m² and the separation between plates is 0.02m. if the dielectrics constant of mica is 7. Find the capacitance of the capacitor?
Anonymous
Jan 11, 2024

The area of one plate of a two plate mica capacitor is 0.0025m² and the separation between plates is 0.02m. if the dielectrics constant of mica is 7. Find the capacitance of the capacitor?

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Jan 11, 2024
The capacitance of a capacitor can be calculated using the formula:

C = (ε₀ * εᵣ * A) / d

where:
C is the capacitance
ε₀ is the permittivity of free space (8.854 x 10⁻¹² F/m)
εᵣ is the relative permittivity (dielectric constant) of the material (7 for mica)
A is the area of one plate (0.0025 m²)
d is the separation between plates (0.02 m)

Plugging in the values:

C = (8.854 x 10⁻¹² F/m * 7 * 0.0025 m²) / 0.02 m
C = (8.854 x 10⁻¹² F/m * 7 * 0.0025 m²) / 0.02 m
C = 0.001239 F

Therefore, the capacitance of the capacitor is approximately 0.001239 Farads.
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