Suppose a small object of 5N is attached to the end of a vertical string.Determine the tension force in the string when the object is moving upward with the uniform velocity?

When the object is moving upward with uniform velocity, the net force acting on the object is zero. This means that the tension force in the string is equal in magnitude to the weight of the object.

The weight of the object can be calculated using the formula:

Weight = mass x acceleration due to gravity

Given that the weight of the object is 5N, we can rearrange the formula to solve for the mass of the object:

mass = Weight / acceleration due to gravity
mass = 5N / 9.8 m/s^2
mass ≈ 0.51 kg

Now that we have the mass of the object, we can calculate the tension force in the string using the formula:

Tension force = Weight + mass x acceleration due to gravity
Tension force = 5N + 0.51 kg x 9.8 m/s^2
Tension force ≈ 10N

Therefore, the tension force in the string when the object is moving upward with uniform velocity is approximately 10N.

When the object is moving upward with a uniform velocity, the net force acting on the object is zero. This means that the tension force in the string must be equal to the weight of the object.

The weight of the object is given by:

$$W = mg$$

where:

- W is the weight of the object in newtons
- m is the mass of the object in kilograms
- g is the acceleration due to gravity in meters per second squared

In this case, the mass of the object is 5N and the acceleration due to gravity is 9.8 m/s2. Therefore, the weight of the object is:

$$W = mg = 5N - 9.8 m/s2 = 49N$$

Therefore, the tension force in the string when the object is moving upward with a uniform velocity is 49N.