Suppose a 0.2kg baseball is traveling at 40m/s. After being hit by a bat, the ball's velocity is 50m/s in the opposite direction.Find average force exerted by bat if ball and bat in constant 0.002s?

To find the average force exerted by the bat, we can use the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied to it.

The change in momentum of the baseball can be calculated as follows:

Initial momentum = mass x initial velocity
= 0.2kg x 40m/s
= 8 kg*m/s

Final momentum = mass x final velocity
= 0.2kg x (-50m/s) [since the final velocity is in the opposite direction]
= -10 kg*m/s

Change in momentum = final momentum - initial momentum
= -10 kg*m/s - 8 kg*m/s
= -18 kg*m/s

The impulse applied to the baseball can be calculated as the change in momentum:

Impulse = change in momentum
= -18 kg*m/s

Now, we can calculate the average force exerted by the bat using the formula:

Impulse = force x time

-18 kg*m/s = force x 0.002s

Force = -18 kg*m/s / 0.002s
Force = -9000 N

Therefore, the average force exerted by the bat on the baseball is 9000 N.

Step 1: Calculate the change in momentum
Momentum is mass times velocity, so the change in momentum is:

```
Δp = mv_f - mv_i
```

where:

- Δp is the change in momentum
- m is the mass of the ball
- v_f is the final velocity of the ball
- v_i is the initial velocity of the ball

Step 2: Calculate the average force applied to the ball
The average force applied to the ball is equal to the rate of change of momentum, which is:

```
F = Δp / Δt
```

where:

- F is the average force
- Δp is the change in momentum
- Δt is the time interval

Step 3: Plug in the values

Plugging in the values, we get:

```
F = (0.2kg - (50m/s - (-40m/s))) / 0.002s
```

```
F = 1800N
```

Therefore, the average force exerted by the bat is 1800N.

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