Steel wire of length 6m & diameter 0.6mm is extended by a force of 60N thehe wire extended by 3mm. Calculate A. applied stress B. The strain on the wire C. The young modules of steel??

To calculate the applied stress, we can use the formula:

Stress = Force / Area

The area of a wire can be calculated using the formula for the area of a circle:

Area = π * (diameter/2)^2

Given that the diameter of the wire is 0.6mm, the radius would be half of that, or 0.3mm (or 0.0003m). Plugging this into the formula, we get:

Area = π * (0.0003)^2 = 0.00000028274334 m^2

Now we can calculate the stress:

Stress = 60N / 0.00000028274334 m^2 = 212,121,212,121.21 N/m^2

So the applied stress is approximately 212,121,212,121.21 N/m^2.

To calculate the strain on the wire, we can use the formula:

Strain = Change in length / Original length

Given that the wire extended by 3mm (or 0.003m), and the original length of the wire is 6m, we can calculate the strain:

Strain = 0.003m / 6m = 0.0005

So the strain on the wire is 0.0005.

To calculate the Young's modulus of steel, we can use the formula:

Young's modulus = Stress / Strain

Plugging in the values we calculated earlier:

Young's modulus = 212,121,212,121.21 N/m^2 / 0.0005 = 424,242,424,242,420 N/m^2

So the Young's modulus of steel is approximately 424,242,424,242,420 N/m^2.