Solve the simultaneous equation using elimination method 8× + 4y =48 3×-4y =7?

To solve this system of equations using the elimination method, we will add the two equations together to eliminate the variable y.

8x + 4y = 48
3x - 4y = 7

Adding the two equations together:

8x + 4y + 3x - 4y = 48 + 7
11x = 55
x = 55 / 11
x = 5

Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:

8x + 4y = 48
8(5) + 4y = 48
40 + 4y = 48
4y = 8
y = 8 / 4
y = 2

Therefore, the solution to the simultaneous equations is x = 5 and y = 2.

Step 1: Multiply the second equation by -2 to make the coefficients of y the same.

```
8x + 4y = 48
-6x + 8y = -14
```

Step 2: Add the two equations together.

```
2x + 12y = 34
```

Step 3: Solve for x.

```
2x = 34 - 12y
x = 17 - 6y
```

Step 4: Substitute the expression for x into the first equation and solve for y.

```
8(17 - 6y) + 4y = 48
136 - 48y + 4y = 48
-44y = -88
y = 2
```

Step 5: Substitute the value of y back into the expression for x to find x.

```
x = 17 - 6(2)
x = 17 - 12
x = 5
```

Therefore, the solution to the simultaneous equations is x = 5 and y = 2.