Sodium and water are mixed, and 0.945 moles of hydrogen is recovered. How many grams of sodium hydroxide will be recovered?

The balanced chemical equation for the reaction between sodium and water is:

2Na + 2H2O -> 2NaOH + H2

From the equation, we can see that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen.

Given that 0.945 moles of hydrogen is recovered, we can calculate the moles of sodium hydroxide produced:

0.945 moles H2 x (2 moles NaOH / 1 mole H2) = 1.89 moles NaOH

Now, we can calculate the mass of sodium hydroxide produced:

1.89 moles NaOH x (40.00 g NaOH / 1 mole NaOH) = 75.6 g NaOH

Therefore, 75.6 grams of sodium hydroxide will be recovered.

Step 1: Write the balanced chemical equation.

```
2 Na + 2 H<sub>2</sub>O → 2 NaOH + H<sub>2</sub>
```

Step 2: Determine the mole ratio between hydrogen and sodium hydroxide.

From the balanced equation, we can see that 2 moles of hydrogen are produced for every 2 moles of sodium hydroxide. Therefore, the mole ratio of H₂ to NaOH is 1:1.

Step 3: Calculate the moles of sodium hydroxide produced.

Since we have 0.945 moles of hydrogen, we will also have 0.945 moles of sodium hydroxide.

Step 4: Convert moles of sodium hydroxide to grams.

The molar mass of sodium hydroxide (NaOH) is 40.00 g/mol. Therefore, the mass of sodium hydroxide produced is:

```
mass of NaOH = moles of NaOH × molar mass of NaOH
```

```
mass of NaOH = 0.945 mol × 40.00 g/mol
```

```
mass of NaOH = 37.80 g
```

Therefore, 37.80 grams of sodium hydroxide will be recovered.