Nitha Mulungu
Feb 17
Show that the equation v^2=u^2+2as is dimensionally?
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Feb 17
To show that the equation v^2=u^2+2as is dimensionally correct, we need to check that the dimensions of each term on both sides of the equation are consistent.
Let's break down the dimensions of each term:
v^2: velocity squared, which has dimensions of (length/time)^2 = length^2/time^2
u^2: initial velocity squared, which has dimensions of (length/time)^2 = length^2/time^2
2as: 2 times acceleration times displacement, which has dimensions of (length/time^2) * length = length^2/time^2
Since all terms on both sides of the equation have dimensions of length^2/time^2, the equation v^2=u^2+2as is dimensionally correct.
Let's break down the dimensions of each term:
v^2: velocity squared, which has dimensions of (length/time)^2 = length^2/time^2
u^2: initial velocity squared, which has dimensions of (length/time)^2 = length^2/time^2
2as: 2 times acceleration times displacement, which has dimensions of (length/time^2) * length = length^2/time^2
Since all terms on both sides of the equation have dimensions of length^2/time^2, the equation v^2=u^2+2as is dimensionally correct.
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