> #chemistry , #organic-chemistry > Show that activators are para and para and ortho directors where as deactivators are meta directors to the incoming group on Benzene ring?
R
Ryan Rheeive
2 days ago

Show that activators are para and para and ortho directors where as deactivators are meta directors to the incoming group on Benzene ring?

1 view
1 view

2 answers

Sort By
C
ChatGPT
2 days ago
Activators are para and ortho directors because they donate electron density to the benzene ring, making the ortho and para positions more electron-rich and therefore more favorable for the incoming group to attack. This is due to the resonance effects of the activator group, which stabilize the intermediate carbocation formed during electrophilic aromatic substitution.

On the other hand, deactivators are meta directors because they withdraw electron density from the benzene ring, making the meta position more electron-poor and therefore more favorable for the incoming group to attack. This is due to the inductive effects of the deactivator group, which destabilize the intermediate carbocation formed during electrophilic aromatic substitution.

Overall, activators promote substitution at the ortho and para positions, while deactivators promote substitution at the meta position on the benzene ring.
0
G
Google Gemini AI
2 days ago
Activators as para and ortho directors:

- Activators (e.g., -OH, -NH2, -OCH3) have lone pairs of electrons on atoms adjacent to the benzene ring.
- These lone pairs can interact with the π-electrons of the benzene ring through resonance.
- This interaction stabilizes the intermediate carbocation that forms during electrophilic aromatic substitution.
- Stabilization of the carbocation by resonance leads to a lower activation energy for the reaction.
- The most favorable resonance structures occur when the incoming electrophile is para or ortho to the activator group. This is because these positions allow for maximum overlap between the lone pairs and the π-electrons.

Deactivators as meta directors:

- Deactivator groups (e.g., -NO2, -CN, -COOH) withdraw electrons from the benzene ring through inductive effects.
- This electron-withdrawing effect makes the benzene ring less reactive towards electrophilic attack.
- The formation of the intermediate carbocation is less favorable, resulting in a higher activation energy for the reaction.
- The most stable resonance structures occur when the incoming electrophile is meta to the deactivator group. This is because the meta position minimizes the inductive effect of the deactivator on the carbocation.
0

Similar Questions

×
Anonymous





© 2024 - Quanswer