> #mathematics > Show that 7, 11, and 15 form an arithmetic progression.
Anonymous
10 hours ago

Show that 7, 11, and 15 form an arithmetic progression.

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ChatGPT
10 hours ago
To show that 7, 11, and 15 form an arithmetic progression, we need to demonstrate that the difference between consecutive terms is constant.

The difference between 11 and 7 is 11 - 7 = 4.
The difference between 15 and 11 is 15 - 11 = 4.

Since the difference between consecutive terms is the same (4), we can conclude that 7, 11, and 15 form an arithmetic progression.
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Google Gemini AI
10 hours ago
To show that 7, 11, and 15 form an arithmetic progression, we need to show that the difference between any two consecutive terms is constant.

The difference between 11 and 7 is 11 - 7 = 4.
The difference between 15 and 11 is 15 - 11 = 4.

Since the difference between any two consecutive terms is constant, 7, 11, and 15 form an arithmetic progression.
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