Okello has a son and two daughters named James, Ann, and Ciss. James is "k" years old, and he is 3 times as old as Ann. Ciss is twice as old as James. The sum of the age of the two daughters is 24.

Let's represent the ages of James, Ann, and Ciss as follows:

James = k years old
Ann = a years old
Ciss = c years old

According to the given information:
1. James is 3 times as old as Ann:
k = 3a

2. Ciss is twice as old as James:
c = 2k

3. The sum of the age of the two daughters is 24:
a + c = 24

Now, we can substitute the values of k and c from equations 1 and 2 into equation 3:

a + 2k = 24
a + 2(3a) = 24
a + 6a = 24
7a = 24
a = 24/7
a = 3.43 (approx.)

Now, we can find the values of k and c using the values of a:

k = 3a
k = 3(3.43)
k = 10.29 (approx.)

c = 2k
c = 2(10.29)
c = 20.58 (approx.)

Therefore, James is approximately 10 years old, Ann is approximately 3 years old, and Ciss is approximately 21 years old.

Given that:
James is "k" years old
Ann is 3 times younger than James, so Ann is k/3 years old
Ciss is twice as old as James, so Ciss is 2k years old
The sum of the age of the two daughters is 24, so Ann + Ciss = 24
Substituting the values of Ann and Ciss, we get:
$$k/3 + 2k = 24$$
Simplifying the equation:
$$7k/3 = 24$$
Multiplying both sides by 3:
$$7k = 72$$
Dividing both sides by 7:
$$k = 10$$
Therefore, James is 10 years old.
Ann is 10/3 = 3.33 years old.
Ciss is 2 - 10 = 20 years old.