Nuetralization reaction 250ml of 0.6M sulphuric acid reaction 400ml of 0.5M potassium hydroxide solution. What is the limiting reactant?

To determine the limiting reactant in this neutralization reaction, we need to compare the number of moles of each reactant present.

First, calculate the number of moles of sulphuric acid:
0.6 mol/L x 0.25 L = 0.15 moles

Next, calculate the number of moles of potassium hydroxide:
0.5 mol/L x 0.4 L = 0.2 moles

Since the number of moles of sulphuric acid (0.15 moles) is less than the number of moles of potassium hydroxide (0.2 moles), the limiting reactant in this reaction is the sulphuric acid.