**Nuclear Decay Series**
- Discuss decay series and chains.
- Illustrate with examples, such as the uranium decay series ?
?
1 view
1 view
1
answer
Sort By
ChatGPT
Feb 17
Decay series, also known as decay chains, refer to the sequence of radioactive decays that a particular radionuclide undergoes until it reaches a stable nuclide. This process involves the emission of alpha particles, beta particles, or gamma rays, resulting in the transformation of the parent radionuclide into a series of daughter nuclides.
One of the most well-known decay series is the uranium decay series, which begins with uranium-238 (U-238) and ends with lead-206 (Pb-206) after a series of alpha and beta decays. The decay chain for U-238 is as follows:
1. Uranium-238 (U-238) undergoes alpha decay to form thorium-234 (Th-234). 2. Thorium-234 (Th-234) undergoes beta decay to form protactinium-234 (Pa-234). 3. Protactinium-234 (Pa-234) undergoes beta decay to form uranium-234 (U-234). 4. Uranium-234 (U-234) undergoes alpha decay to form thorium-230 (Th-230). 5. Thorium-230 (Th-230) undergoes alpha decay to form radium-226 (Ra-226). 6. Radium-226 (Ra-226) undergoes alpha decay to form radon-222 (Rn-222). 7. Radon-222 (Rn-222) undergoes alpha decay to form polonium-218 (Po-218). 8. Polonium-218 (Po-218) undergoes alpha decay to form lead-214 (Pb-214). 9. Lead-214 (Pb-214) undergoes beta decay to form bismuth-214 (Bi-214). 10. Bismuth-214 (Bi-214) undergoes beta decay to form polonium-214 (Po-214). 11. Polonium-214 (Po-214) undergoes alpha decay to form lead-210 (Pb-210). 12. Lead-210 (Pb-210) undergoes beta decay to form bismuth-210 (Bi-210). 13. Bismuth-210 (Bi-210) undergoes beta decay to form polonium-210 (Po-210). 14. Polonium-210 (Po-210) undergoes alpha decay to form lead-206 (Pb-206), which is stable.
This decay series illustrates the transformation of uranium-238 into lead-206 through a series of radioactive decays. Decay series are important in understanding the behavior of radioactive elements and their eventual decay into stable nuclides.