Musa is 18 years old and asaphis is 42 years older now. After how many years will asaphis's age be twice musa's age?

Let x be the number of years after which Asaphis's age will be twice Musa's age.

After x years, Musa will be 18 + x years old and Asaphis will be 18 + x + 42 = 60 + x years old.

According to the given condition, Asaphis's age will be twice Musa's age after x years:

60 + x = 2(18 + x)

60 + x = 36 + 2x

Subtracting x from both sides:

60 = 36 + x

Subtracting 36 from both sides:

24 = x

Therefore, after 24 years, Asaphis's age will be twice Musa's age.

Let's assume the number of years to pass is x.

After x years:
Musa's age = 18 + x
Asaphis's age = 42 + 18 + x = 60 + x

According to the question, asaphis's age will be twice musa's age after x years. So, we can write:
60 + x = 2(18 + x)

Simplifying the equation:
60 + x = 36 + 2x
x - 2x = 60 - 36
-x = 24
x = -24

However, the number of years to pass cannot be negative. Therefore, there is no valid solution to this problem.