Mr.wangila saved sh.5 coins and sh.10 coins in a can.There are 14 coins in total and their value is sh.105.Find the number of each type of coins?

Let x be the number of sh.5 coins and y be the number of sh.10 coins.

From the given information, we can create the following system of equations:

x + y = 14 (total number of coins)
5x + 10y = 105 (total value of coins)

Solving the system of equations, we get:
x = 9
y = 5

Therefore, Mr. Wangila saved 9 sh.5 coins and 5 sh.10 coins.

Let the number of sh.5 coins be x and the number of sh.10 coins be y.

From the given information, we have:

x + y = 14 (total number of coins)
5x + 10y = 105 (total value of coins)

Solving these equations simultaneously, we get:

x = 7 (number of sh.5 coins)
y = 7 (number of sh.10 coins)

Therefore, there are 7 sh.5 coins and 7 sh.10 coins in the can.