In [PtCl(No2)(NH3)]SO4 the oxidation number of platinum is?

The oxidation number of Pt in [PtCl(NO2)(NH3)]SO4 can be calculated as follows:

Let x be the oxidation number of Pt.

The oxidation number of Cl is -1, NO2 is -1, NH3 is 0, and SO4 is -2.

Therefore, the sum of the oxidation numbers in the compound must equal the charge of the compound, which is 0.

x + (-1) + (-1) + 0 + 0 + (-2) = 0
x - 4 = 0
x = +4

Therefore, the oxidation number of platinum (Pt) in [PtCl(NO2)(NH3)]SO4 is +4.

+4