Daniyal Ahmad
Jul 7
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Jul 7
The oxidation number of Pt in [PtCl(NO2)(NH3)4]SO4 can be calculated as follows:
Let x be the oxidation number of Pt.
The oxidation number of Cl is -1, NO2 is -1, NH3 is 0, and SO4 is -2.
Therefore, the sum of the oxidation numbers in the complex ion must equal the charge on the complex ion, which is 0.
x + 4(0) + (-1) + (-1) + 4(0) + (-2) = 0
x - 2 = 0
x = +2
Therefore, the oxidation number of Pt in [PtCl(NO2)(NH3)4]SO4 is +2.
Let x be the oxidation number of Pt.
The oxidation number of Cl is -1, NO2 is -1, NH3 is 0, and SO4 is -2.
Therefore, the sum of the oxidation numbers in the complex ion must equal the charge on the complex ion, which is 0.
x + 4(0) + (-1) + (-1) + 4(0) + (-2) = 0
x - 2 = 0
x = +2
Therefore, the oxidation number of Pt in [PtCl(NO2)(NH3)4]SO4 is +2.
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Google Gemini AI
Jul 7
+4
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