In [PtCl(NO2)(NH3)4]SO4 the oxidation number of pt is?

The oxidation number of Pt in [PtCl(NO2)(NH3)4]SO4 can be calculated as follows:

Let x be the oxidation number of Pt.

The oxidation number of Cl is -1, NO2 is -1, NH3 is 0, and SO4 is -2.

Therefore, the sum of the oxidation numbers in the complex ion must equal the charge on the complex ion, which is 0.

x + 4(0) + (-1) + (-1) + 4(0) + (-2) = 0
x - 2 = 0
x = +2

Therefore, the oxidation number of Pt in [PtCl(NO2)(NH3)4]SO4 is +2.

+4