In a class of 60 students,30 offered physics and 40 offer chemistry.If a student is picked random from the class what is the probability that the student offers both physics and chemistry?

To find the probability that a student offers both physics and chemistry, we need to determine the number of students who offer both subjects and divide it by the total number of students in the class.

Let's denote the number of students who offer both physics and chemistry as "x". We know that 30 students offer physics and 40 students offer chemistry. Since there are only 60 students in total, the maximum number of students who can offer both subjects is 30 (the number of students who offer physics).

Therefore, the number of students who offer both physics and chemistry is between 0 and 30, inclusive.

The probability that a student offers both physics and chemistry is given by:

P(Physics and Chemistry) = x / 60

Since we don't have the exact value of "x", we cannot determine the exact probability. However, we can say that the probability is between 0 and 30/60, which simplifies to 1/2 or 0.5.

So, the probability that a student picked randomly from the class offers both physics and chemistry is 0.5 or 50%.