If the elastic band is stretched by 5 mm when a force of 80N is applied, what is the strain on its end?

To calculate the strain on the end of the elastic band, we can use the formula:

Strain = (Change in length) / (Original length)

Given that the elastic band is stretched by 5 mm (0.005 m) and the force applied is 80N, we can calculate the strain as follows:

Strain = (0.005 m) / (Original length)

To find the original length, we need to use Hooke's Law, which states that the force applied is directly proportional to the extension of the elastic band. Therefore, we can write:

F = k * x

Where:
F = Force applied (80N)
k = Spring constant
x = Extension of the elastic band (0.005 m)

Rearranging the formula to solve for the spring constant:

k = F / x
k = 80N / 0.005 m
k = 16000 N/m

Now, we can find the original length of the elastic band by rearranging Hooke's Law:

x = F / k
x = 80N / 16000 N/m
x = 0.005 m

Now that we have the original length, we can calculate the strain:

Strain = (0.005 m) / (0.005 m)
Strain = 1

Therefore, the strain on the end of the elastic band is 1.