If the alternating current as function of time in an AC heating coil is given by the expression I = 5.6 sin 120×3.14t, what is the peak current (IP) ?

The peak current (IP) is the maximum value of the current in the AC heating coil. In this case, the peak current can be found by looking at the coefficient of the sine function, which is 5.6.

Therefore, the peak current (IP) is 5.6.

The peak current (IP) in an AC circuit is given by the amplitude of the current waveform. In this case, the amplitude is 5.6 amps. Therefore, the peak current is:

IP = 5.6 amps