If excess of iron then production of fecl3 require how much gram of cl?

To determine how much gram of Cl is required for the production of FeCl3 when there is an excess of iron, we need to consider the stoichiometry of the reaction.

The reaction between iron and chlorine to produce iron(III) chloride is as follows:

2Fe + 3Cl2 -> 2FeCl3

From the balanced equation, we can see that 3 moles of Cl2 are required to produce 2 moles of FeCl3. This means that the molar ratio of Cl2 to FeCl3 is 3:2.

Since we have an excess of iron, we need to calculate the amount of Cl2 required to react with all the iron present. If we assume that 1 mole of iron is present, then we would need 3/2 moles of Cl2 to react with it.

The molar mass of Cl2 is approximately 70.9 g/mol. Therefore, the mass of Cl2 required would be:

(3/2) * 70.9 g = 106.35 g

So, if there is an excess of iron, 106.35 grams of Cl2 would be required to produce FeCl3.

3 mol of fecl3