Identify the pressure exerted on the earth walls at the base of the wall, if the earth walls have a density of 2000kg/m3 and the earth walls are 5 metres tall and 1 metre thick at the base?

To calculate the pressure exerted on the earth walls at the base of the wall, we need to first calculate the weight of the earth walls.

Volume of the earth walls = 5m (height) x 1m (thickness) x 1m (width) = 5m^3

Weight of the earth walls = Volume x Density = 5m^3 x 2000kg/m^3 = 10000kg

Now, we need to calculate the area of the base of the wall to determine the pressure exerted.

Area of the base of the wall = 1m (thickness) x 1m (width) = 1m^2

Pressure = Weight/Area = 10000kg / 1m^2 = 10000 Pa

Therefore, the pressure exerted on the earth walls at the base of the wall is 10000 Pascal.

The pressure at the base of the wall is given by the formula:

$$P = \rho g h$$

where:

- P is the pressure in Pa
- rho is the density of the fluid in kg/m^3
- g is the acceleration due to gravity in m/s^2
- h is the height of the fluid in m

In this case, the fluid is earth, the density of the earth is 2000 kg/m^3, the acceleration due to gravity is 9.81 m/s^2, and the height of the earth is 5 meters.

Substituting these values into the formula, we get:

$$P = 2000 kg/m^3 - 9.81 m/s^2 - 5 m = 98100 Pa$$

Therefore, the pressure exerted on the earth walls at the base of the wall is 98100 Pa.