Hydrogen gas reacts with chloride that is formed if 45 cm cubed of chlorine reacted with 50 cm cubed of hydrogen. calculate Total volume of the gas at the end of the equation?

To find the total volume of gas at the end of the equation, we first need to determine the limiting reactant in the reaction between hydrogen gas and chlorine gas.

The balanced chemical equation for the reaction is:

H2 + Cl2 -> 2HCl

From the equation, we can see that 1 mole of hydrogen gas reacts with 1 mole of chlorine gas to produce 2 moles of hydrogen chloride gas.

First, we need to calculate the number of moles of each reactant:

For hydrogen gas:
Volume of hydrogen gas = 50 cm^3
Molar volume of gas at STP = 22.4 L/mol
Number of moles of hydrogen gas = 50 cm^3 / 1000 cm^3/L * 1 L/1000 cm^3 * 1 mol/22.4 L = 0.002232 moles

For chlorine gas:
Volume of chlorine gas = 45 cm^3
Number of moles of chlorine gas = 45 cm^3 / 1000 cm^3/L * 1 L/1000 cm^3 * 1 mol/22.4 L = 0.002008 moles

Since the reaction ratio is 1:1 for hydrogen and chlorine, the limiting reactant is the one that produces the least amount of product, which is chlorine in this case.

Therefore, all of the chlorine gas will react with the hydrogen gas to produce hydrogen chloride gas. The total volume of gas at the end of the equation will be the sum of the volumes of hydrogen gas and chlorine gas:

Total volume of gas = 50 cm^3 + 45 cm^3 = 95 cm^3

Therefore, the total volume of gas at the end of the equation is 95 cm^3.

The balanced chemical equation for the reaction between hydrogen and chlorine is:

```
H2 + Cl2 → 2HCl
```

According to the equation, 1 volume of hydrogen reacts with 1 volume of chlorine to produce 2 volumes of hydrogen chloride.

Therefore, if 45 cm³ of chlorine reacted with 50 cm³ of hydrogen, the total volume of hydrogen chloride produced will be:

```
2 × (45 cm³ + 50 cm³) = 190 cm³
```

Therefore, the total volume of the gas at the end of the equation is 190 cm³.