Huiu?

To determine the position d of the 6kN load so that the average normal stress in each rod is the same, we need to consider the equilibrium of forces and the stress in each rod.

Let's assume that the distance from point A to the position of the 6kN load is x. Therefore, the distance from the position of the 6kN load to point C is (d - x).

First, let's calculate the stress in rod AB. The stress in a rod is given by the formula:

Stress = Force / Area

The force in rod AB is the sum of the forces acting on it, which are the 6kN load and the reaction force at point A. The reaction force at point A can be calculated using the equilibrium of forces:

6kN + Reaction force at A = 0

Therefore, the reaction force at A is -6kN.

Now, let's calculate the stress in rod AB:

Stress_AB = (6kN - 6kN) / 16mm^2
= 0 / 16mm^2
= 0

Next, let's calculate the stress in rod AC. The force in rod AC is the sum of the forces acting on it, which are the 6kN load and the reaction force at point C. The reaction force at point C can be calculated using the equilibrium of forces:

6kN + Reaction force at C = 0

Therefore, the reaction force at C is -6kN.

Now, let's calculate the stress in rod AC:

Stress_AC = (6kN - 6kN) / 10mm^2
= 0 / 10mm^2
= 0

Since the stress in both rods is zero, the average normal stress in each rod is the same.

Therefore, the position d of the 6kN load can be any value, as long as it is within the range of the rods AB and AC.