How many moles of NaHCO3 are required to neutralize 9 mL of H2SO4?

To determine the number of moles of NaHCO3 required to neutralize 9 mL of H2SO4, we first need to calculate the number of moles of H2SO4 present in 9 mL of the solution.

Given that the molarity of H2SO4 is not provided, we cannot directly calculate the number of moles of H2SO4. However, we can make an assumption that the concentration of H2SO4 is 1 M (which is a common concentration for sulfuric acid solutions).

The molar mass of H2SO4 is 98.08 g/mol.

Using the formula:
Molarity (M) = moles of solute / volume of solution (L)

We can calculate the number of moles of H2SO4 in 9 mL of 1 M solution:
Moles of H2SO4 = Molarity x Volume
Moles of H2SO4 = 1 mol/L x 0.009 L
Moles of H2SO4 = 0.009 moles

Since the reaction between NaHCO3 and H2SO4 is a 1:1 ratio, the number of moles of NaHCO3 required to neutralize 0.009 moles of H2SO4 is also 0.009 moles.

Therefore, 0.009 moles of NaHCO3 are required to neutralize 9 mL of H2SO4.

Step 1: Determine the concentration of sulfuric acid.

The given information does not provide the concentration of sulfuric acid. Therefore, we cannot proceed with the calculation.