Abubeker Eliyas
Jun 2
How many integers can be represented using the digit 3,5,7,9 with each digit used at most once in numeral?
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Jun 2
There are 24 integers that can be represented using the digits 3, 5, 7, and 9 with each digit used at most once in the numeral.
This can be calculated by finding the number of permutations of the 4 digits (4!) and subtracting the number of permutations where the first digit is 0 (3!).
Therefore, 4! - 3! = 24 - 6 = 18.
So, there are 18 integers that can be represented using the digits 3, 5, 7, and 9 with each digit used at most once in the numeral.
This can be calculated by finding the number of permutations of the 4 digits (4!) and subtracting the number of permutations where the first digit is 0 (3!).
Therefore, 4! - 3! = 24 - 6 = 18.
So, there are 18 integers that can be represented using the digits 3, 5, 7, and 9 with each digit used at most once in the numeral.
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