How long (in minutes) will it take 4800J of electrical energy to flow through the 10 ohm resistor?

To calculate the time it will take for 4800J of electrical energy to flow through a 10 ohm resistor, we can use the formula:

Energy (J) = Power (W) x Time (s)

First, we need to calculate the power (W) using the formula:

Power (W) = Energy (J) / Time (s)

Given that the energy is 4800J and the resistance is 10 ohms, we can use Ohm's Law to calculate the power:

Power (W) = (Voltage^2) / Resistance

Voltage = sqrt(Power x Resistance)
Voltage = sqrt(4800 x 10) = sqrt(48000) = 219.09 V

Now we can calculate the power:

Power (W) = (219.09^2) / 10 = 4788.18 W

Now we can rearrange the formula to solve for time:

Time (s) = Energy (J) / Power (W)
Time (s) = 4800 / 4788.18 = 1.002 seconds

Therefore, it will take approximately 1.002 seconds for 4800J of electrical energy to flow through the 10 ohm resistor.

P = IV

V = IR

P = I^2 - R

t = E/P

t = E/I^2 - R

t = (4800J)/(I^2 - 10 ohm)

We need to find the current (I) flowing through the resistor using Ohm's Law:

V = IR

I = V/R

I = 12V/10 ohm

I = 1.2A

Substituting the value of I into the equation for time (t):

t = (4800J)/(1.2A)^2 - 10 ohm

t = 333.33 minutes

Therefore, it will take 333.33 minutes for 4800J of electrical energy to flow through the 10 ohm resistor.