How does the splitting pattern of 1-chloropropane differ from 2-chloropropane in ^1H NMR spectra?

In the ^1H NMR spectra of 1-chloropropane, the hydrogen atoms on the adjacent carbon atoms are not equivalent, resulting in a splitting pattern. The hydrogen atoms on the carbon adjacent to the chlorine atom will be split into a doublet by the hydrogen atom on the carbon next to it.

In contrast, in the ^1H NMR spectra of 2-chloropropane, the hydrogen atoms on the adjacent carbon atoms are equivalent, so there will be no splitting pattern. The hydrogen atoms on the carbon adjacent to the chlorine atom will appear as a singlet.

Therefore, the splitting pattern in the ^1H NMR spectra of 1-chloropropane will be more complex compared to 2-chloropropane due to the presence of neighboring hydrogen atoms that are not equivalent.

1-Chloropropane has the following structure: CH3-CH2-CH2-Cl. The proton attached to the carbon adjacent to the chlorine atom (C-2) will split the proton signal on C-3 into a triplet with a coupling constant of approximately 7 Hz.

2-Chloropropane has the following structure: CH3-CH(Cl)-CH3. The protons on C-3 will split the proton signal on C-2 into a doublet with a coupling constant of approximately 7 Hz. However, the proton on C-3 is also split by the proton on C-2, resulting in a doublet of doublets with coupling constants of approximately 7 Hz each.