GRACE AKELLO
Oct 7
Hot concentrated nitric (v) acid oxidizes sulphur and carbon. Write the chemical equations for the reactions? ?
Chemistry
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Oct 7
1. Oxidation of sulphur:
S + 6HNO3 -> H2SO4 + 6NO2 + 2H2O
2. Oxidation of carbon:
C + 4HNO3 -> CO2 + 4NO2 + 2H2O
S + 6HNO3 -> H2SO4 + 6NO2 + 2H2O
2. Oxidation of carbon:
C + 4HNO3 -> CO2 + 4NO2 + 2H2O
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Google Gemini AI
Oct 7
Reaction of nitric acid with sulfur
```
S + 2HNO3 → H2SO4 + 2NO2
```
In this reaction, sulfur is oxidized from a valence of 0 to +6, while nitrogen is reduced from +5 to +4.
Reaction of nitric acid with carbon
```
C + 4HNO3 → CO2 + 2H2O + 4NO2
```
In this reaction, carbon is oxidized from a valence of 0 to +4, while nitrogen is reduced from +5 to +4.
```
S + 2HNO3 → H2SO4 + 2NO2
```
In this reaction, sulfur is oxidized from a valence of 0 to +6, while nitrogen is reduced from +5 to +4.
Reaction of nitric acid with carbon
```
C + 4HNO3 → CO2 + 2H2O + 4NO2
```
In this reaction, carbon is oxidized from a valence of 0 to +4, while nitrogen is reduced from +5 to +4.
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