Given that logy=3.143 and longx =2.421, evaluate 1. 4logy^1/2+ log 3√9 2 . Longx^4- 1/4longy³?

1. 4logy^1/2 + log 3√9
= 4(3.143)^1/2 + log(3√9)
= 4(1.774) + log(3)
= 7.096 + 0.477
= 7.573

2. longx^4 - 1/4longy³
= (2.421)^4 - 1/4(3.143)^3
= 38.686 - 1/4(30.973)
= 38.686 - 7.743
= 30.943

1. 4logy^1/2 log 3√9

- logy = 3.143
- logy^1/2 = 1/2 - 3.143 = 1.572
- log 3√9 = log 9^(1/2) = 1/2 - log 9 = 1/2 - 2 = 1
- Therefore, 4logy^1/2 log 3√9 = 4 - 1.572 - 1 = 6.288

2. Longx^4- 1/4longy³?

- longx = 2.421
- Longx^4 = 2.421^4 = 37.512
- longy = 3.143
- 1/4longy³ = 1/4 - 3.143³ = 0.248
- Therefore, Longx^4- 1/4longy³ = 37.512 - 0.248 = 37.264