GRACE AKELLO
3 hours ago
Given sodium carbonate solid, lead (11) nitrate solid and water, explain how a sample of lead (11) carbonate can be obtained? ?
Chemistry
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ChatGPT
3 hours ago
To obtain a sample of lead (II) carbonate from sodium carbonate and lead (II) nitrate, you can follow these steps:
1. Dissolve sodium carbonate solid in water to form a solution.
2. Dissolve lead (II) nitrate solid in water to form a separate solution.
3. Slowly pour the lead (II) nitrate solution into the sodium carbonate solution while stirring continuously. A white precipitate of lead (II) carbonate will form.
4. Filter the mixture to separate the solid lead (II) carbonate from the remaining solution.
5. Wash the lead (II) carbonate with distilled water to remove any impurities.
6. Dry the lead (II) carbonate by placing it in an oven at a low temperature or allowing it to air dry.
7. Once the lead (II) carbonate is completely dry, it can be collected as a sample for further analysis or use.
1. Dissolve sodium carbonate solid in water to form a solution.
2. Dissolve lead (II) nitrate solid in water to form a separate solution.
3. Slowly pour the lead (II) nitrate solution into the sodium carbonate solution while stirring continuously. A white precipitate of lead (II) carbonate will form.
4. Filter the mixture to separate the solid lead (II) carbonate from the remaining solution.
5. Wash the lead (II) carbonate with distilled water to remove any impurities.
6. Dry the lead (II) carbonate by placing it in an oven at a low temperature or allowing it to air dry.
7. Once the lead (II) carbonate is completely dry, it can be collected as a sample for further analysis or use.
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Google Gemini AI
3 hours ago
Materials:
- Sodium carbonate solid (Na2CO3)
- Lead(II) nitrate solid (Pb(NO3)2)
- Water (H2O)
Procedure:
1. Dissolve the reactants: Add a small amount of sodium carbonate solid to a beaker of water. Stir to dissolve. Add a small amount of lead(II) nitrate solid to a separate beaker of water and stir to dissolve.
2. Combine the solutions: Gradually add the lead(II) nitrate solution to the sodium carbonate solution while stirring.
3. Observe the reaction: A white precipitate of lead(II) carbonate (PbCO3) will form immediately.
4. Filter the precipitate: Filter the solution through a funnel lined with filter paper to separate the lead(II) carbonate precipitate from the supernatant liquid.
5. Wash and dry the precipitate: Rinse the precipitate with distilled water to remove any remaining растворенных impurities. Transfer the precipitate to a clean filter paper and allow it to dry completely.
Chemical Equation:
Na2CO3(aq) + Pb(NO3)2(aq) → PbCO3(s) + 2NaNO3(aq)
Explanation:
In this reaction, sodium carbonate and lead(II) nitrate dissolve in water to form sodium and nitrate ions, respectively. The sodium and nitrate ions remain in solution, while the lead(II) and carbonate ions combine to form an insoluble solid, lead(II) carbonate. This precipitate is removed from the solution by filtration, leaving a clear supernatant liquid containing sodium nitrate.
- Sodium carbonate solid (Na2CO3)
- Lead(II) nitrate solid (Pb(NO3)2)
- Water (H2O)
Procedure:
1. Dissolve the reactants: Add a small amount of sodium carbonate solid to a beaker of water. Stir to dissolve. Add a small amount of lead(II) nitrate solid to a separate beaker of water and stir to dissolve.
2. Combine the solutions: Gradually add the lead(II) nitrate solution to the sodium carbonate solution while stirring.
3. Observe the reaction: A white precipitate of lead(II) carbonate (PbCO3) will form immediately.
4. Filter the precipitate: Filter the solution through a funnel lined with filter paper to separate the lead(II) carbonate precipitate from the supernatant liquid.
5. Wash and dry the precipitate: Rinse the precipitate with distilled water to remove any remaining растворенных impurities. Transfer the precipitate to a clean filter paper and allow it to dry completely.
Chemical Equation:
Na2CO3(aq) + Pb(NO3)2(aq) → PbCO3(s) + 2NaNO3(aq)
Explanation:
In this reaction, sodium carbonate and lead(II) nitrate dissolve in water to form sodium and nitrate ions, respectively. The sodium and nitrate ions remain in solution, while the lead(II) and carbonate ions combine to form an insoluble solid, lead(II) carbonate. This precipitate is removed from the solution by filtration, leaving a clear supernatant liquid containing sodium nitrate.
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