Find the resultant force on the engine when the a force of 20N pulled the engine upwards, 16N pulled the engine downwards and 3N pulled the engine eastwards ?

To find the resultant force on the engine, we need to break down the forces into their horizontal and vertical components.

Given:
- Force pulling the engine upwards = 20N
- Force pulling the engine downwards = 16N
- Force pulling the engine eastwards = 3N

Vertical forces:
Upwards force = 20N
Downwards force = 16N

Resultant vertical force = 20N - 16N = 4N upwards

Horizontal forces:
Eastwards force = 3N

Resultant horizontal force = 3N eastwards

Now, we can find the magnitude and direction of the resultant force using the Pythagorean theorem:

Resultant force = sqrt((4N)^2 + (3N)^2)
Resultant force = sqrt(16 + 9)
Resultant force = sqrt(25)
Resultant force = 5N

Therefore, the resultant force on the engine is 5N, directed at an angle of tan^(-1)(4/3) = 53.13 degrees north of east.

Step 1: Calculate the net upward force

Net upward force = Upward force - Downward force
Net upward force = 20 N - 16 N
Net upward force = 4 N

Step 2: Calculate the net horizontal force

Net horizontal force = Eastward force
Net horizontal force = 3 N

Step 3: Use the Pythagorean theorem to find the magnitude of the resultant force

Resultant force = √(Net upward force^2 + Net horizontal force^2)
Resultant force = √(4 N^2 + 3 N^2)
Resultant force = √(16 N^2 + 9 N^2)
Resultant force = √(25 N^2)

Resultant force = 5 N

Therefore, the resultant force on the engine is 5 N.

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