Find the number of ways of selecting a set of three DVD from a collection from a team of 8 DVDs.a.336,b.168,c.28, d.56?

The number of ways of selecting a set of three DVDs from a collection of 8 DVDs can be calculated using the combination formula:

C(n, r) = n! / (r!(n-r)!)

Where n is the total number of items (8 DVDs) and r is the number of items to be selected (3 DVDs).

C(8, 3) = 8! / (3!(8-3)!)
C(8, 3) = 8! / (3!5!)
C(8, 3) = (8*7*6) / (3*2*1)
C(8, 3) = 56

Therefore, the number of ways of selecting a set of three DVDs from a collection of 8 DVDs is 56.

So, the correct answer is d. 56.

The number of ways of selecting a set of three DVDs from a collection of 8 DVDs is:

$$^8C_3 = \frac{8!}{3!(8-3)!} = \frac{8!}{3!5!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56$$

Therefore, the answer is d. 56.