Find the equation of the straight line that passes through (2,1) and is parallel to y=2x + 5?

Since the line we are looking for is parallel to y=2x+5, it will have the same slope of 2.

The equation of a line with slope m passing through point (x1, y1) is given by y - y1 = m(x - x1).

Substitute the values of the point (2,1) and the slope m=2 into the equation:

y - 1 = 2(x - 2)
y - 1 = 2x - 4
y = 2x - 3

Therefore, the equation of the straight line that passes through (2,1) and is parallel to y=2x + 5 is y = 2x - 3.

The equation of a straight line is given by y = mx + c, where m is the slope and c is the y-intercept.

Since the line is parallel to y = 2x + 5, it has the same slope as y = 2x + 5, which is 2.

So, the slope of the line is m = 2.

We are given that the line passes through the point (2,1). Substituting these values into the equation y = mx + c, we get:

1 = 2(2) + c
1 = 4 + c
c = -3

Therefore, the equation of the straight line is y = 2x - 3.