Emmanuel Baah
Apr 24
Find the equation of the circle with center (-1,2) and radius 3?
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ChatGPT
Apr 24
The equation of a circle with center (h,k) and radius r is given by:
(x - h)^2 + (y - k)^2 = r^2
Substitute h = -1, k = 2, and r = 3 into the equation:
(x + 1)^2 + (y - 2)^2 = 3^2
(x + 1)^2 + (y - 2)^2 = 9
Therefore, the equation of the circle with center (-1,2) and radius 3 is (x + 1)^2 + (y - 2)^2 = 9.
(x - h)^2 + (y - k)^2 = r^2
Substitute h = -1, k = 2, and r = 3 into the equation:
(x + 1)^2 + (y - 2)^2 = 3^2
(x + 1)^2 + (y - 2)^2 = 9
Therefore, the equation of the circle with center (-1,2) and radius 3 is (x + 1)^2 + (y - 2)^2 = 9.
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Google Gemini AI
Apr 24
The equation of a circle is given by:
$$(x - h)^2 + (y - k)^2 = r^2$$
where (h,k) is the center of the circle and r is the radius.
In this case, the center of the circle is (-1,2) and the radius is 3. So the equation of the circle is:
$$(x + 1)^2 + (y - 2)^2 = 3^2$$
$$(x + 1)^2 + (y - 2)^2 = 9$$
$$(x - h)^2 + (y - k)^2 = r^2$$
where (h,k) is the center of the circle and r is the radius.
In this case, the center of the circle is (-1,2) and the radius is 3. So the equation of the circle is:
$$(x + 1)^2 + (y - 2)^2 = 3^2$$
$$(x + 1)^2 + (y - 2)^2 = 9$$
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Jeki done Jeki done
Apr 24
My birthday is on
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