find the absolute maximum or minimum of the function f(x)=-3x^4)+(8x^3)-10 [0,3]. ?

To find the absolute maximum or minimum of the function f(x)=-3x^4+8x^3-10 on the interval [0,3], we first need to find the critical points of the function within the interval.

Taking the derivative of the function:
f'(x) = -12x^3 + 24x^2

Setting f'(x) equal to 0 to find critical points:
-12x^3 + 24x^2 = 0
-12x^2(x - 2) = 0
x = 0 or x = 2

Now we need to evaluate the function at the critical points and the endpoints of the interval:
f(0) = -10
f(2) = -10
f(3) = -19

Therefore, the absolute maximum of the function on the interval [0,3] is -10 and the absolute minimum is -19.