Figure below shows a pulley system used to hoist a load of 3200N. Assuming the friction at the fixed pulley is 96, calculate the, Effort required to lift the load to that height. Neglect the weight ?

To calculate the effort required to lift the load, we need to consider the forces acting on the system.

Given:
Load = 3200 N
Friction at fixed pulley = 96 N

Since the load is being lifted, the tension in the rope on both sides of the pulley system will be the same. Let T be the tension in the rope.

The forces acting on the load are:
1. Tension in the rope on the left side of the fixed pulley = T
2. Tension in the rope on the right side of the fixed pulley = T
3. Weight of the load = 3200 N
4. Friction at the fixed pulley = 96 N

Since the load is in equilibrium, the sum of the forces in the vertical direction must be zero:

T + T - 3200 - 96 = 0
2T - 3296 = 0
2T = 3296
T = 1648 N

Therefore, the effort required to lift the load to that height is 1648 N.

Given:
- Load: 3200N
- Number of movable pulleys: 3
- Friction at fixed pulley: 96N

Mechanical Advantage (MA) of the pulley system:
MA = (2^n) - (Mechanical Advantage of fixed pulley)
MA = (2^3) - (1-friction/load)
MA = 8 - (1-96/3200)
MA = 8 - (1-0.03)
MA = 7.75

Effort required to lift the load:
Effort = Load / Mechanical Advantage
Effort = 3200N / 7.75
Effort = 412.9N

Therefore, the effort required to lift the load to that height is 412.9N.