Factorise y= -3x^2 +2x -1 ?

To factorise the quadratic equation y = -3x^2 + 2x - 1, we need to find two numbers that multiply to -3 (-3 is the coefficient of x^2), and add up to 2 (2 is the coefficient of x).

The two numbers that satisfy these conditions are 3 and -1. Therefore, we can rewrite the equation as:

y = -3x^2 + 3x - x - 1

Now, we can factor by grouping:

y = -3x(x - 1) + 1(x - 1)

y = (x - 1)(-3x + 1)

Therefore, the factorised form of the equation y = -3x^2 + 2x - 1 is y = (x - 1)(-3x + 1).

y = -3x^2 + 2x - 1

= -3x^2 + 3x - x - 1

= -3x(x - 1) - 1(x - 1)

= (x - 1)(-3x - 1)