Factoring y= 2(x+1)(x^2 + 1) ?

To factor the expression y= 2(x+1)(x^2 + 1), we can first distribute the 2 to both terms inside the parentheses:

y = 2x(x^2 + 1) + 2(x^2 + 1)

Now, we can further simplify by distributing the x to the terms inside the parentheses:

y = 2x^3 + 2x + 2x^2 + 2

Combining like terms, we get:

y = 2x^3 + 2x^2 + 2x + 2

Therefore, the factored form of y= 2(x+1)(x^2 + 1) is 2x^3 + 2x^2 + 2x + 2.

y = 2(x - 1)(x^2 + 1)

This factors as:

y = 2(x - 1)(x + i)(x - i)

where i is the imaginary unit, i.e., i^2 = -1.