Determine Vb,Ve,Vc,Vce,Ib,Ib,Ic. The 2N3904 is general purpose transistor with a typical Bdc=100 "?" ?

Given that the 2N3904 is a general purpose transistor with a typical DC current gain (Beta) of 100, we can determine the values of Vb, Ve, Vc, Vce, Ib, Ie, and Ic using the following information:

Assuming the transistor is in active mode:

1. Vb = 0.7V (base-emitter voltage drop)
2. Ve = Vb = 0.7V
3. Vc = Vcc - Ic*Rc (collector voltage)
4. Vce = Vc - Ve (collector-emitter voltage)
5. Ib = (Vcc - Vb) / Rb (base current)
6. Ie = Ib * Beta (emitter current)
7. Ic = Ie (collector current)

Where:
- Vcc is the supply voltage
- Rc is the collector resistor
- Rb is the base resistor

Please provide the values of Vcc, Rc, and Rb in order to calculate the specific values of Vb, Ve, Vc, Vce, Ib, Ie, and Ic.