Determine the volume occupied by 2kg of an ideal gas at 120kpa and 300k. Assume suitable value of gass constant?

To determine the volume occupied by 2kg of an ideal gas at 120kPa and 300K, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in Pa)
V = volume (in m^3)
n = number of moles of gas
R = gas constant (in J/(mol·K))
T = temperature (in K)

First, we need to calculate the number of moles of gas using the given mass and the molar mass of the gas. Let's assume the gas is nitrogen (N2), which has a molar mass of approximately 28 g/mol.

Number of moles (n) = mass / molar mass
n = 2 kg / (28 g/mol * 0.001 kg/g)
n = 71.43 mol

Next, we need to determine the gas constant suitable for the units we are using. The ideal gas constant (R) can be expressed in different units, but the most commonly used value is 8.314 J/(mol·K).

Now we can rearrange the ideal gas law equation to solve for volume (V):

V = (nRT) / P

V = (71.43 mol * 8.314 J/(mol·K) * 300 K) / 120,000 Pa
V = 0.149 m^3

Therefore, the volume occupied by 2kg of an ideal gas at 120kPa and 300K is approximately 0.149 m^3.

1.435