Derive an expression for impedance of series R-C circuit ?

The impedance of a series R-C circuit can be calculated by adding the impedance of the resistor (R) and the impedance of the capacitor (C) in series.

The impedance of a resistor is simply its resistance value (R), so the impedance of the resistor in the series R-C circuit is R.

The impedance of a capacitor is given by the formula:

Zc = 1 / (jωC)

Where:
Zc = Impedance of the capacitor
j = Imaginary unit
ω = Angular frequency (2πf)
C = Capacitance of the capacitor

Therefore, the total impedance (Z) of the series R-C circuit is:

Z = R + 1 / (jωC)

Simplifying this expression, we get:

Z = R + 1 / (jωC)
Z = R + 1 / jωC
Z = R - j / ωC

So, the impedance of a series R-C circuit is given by the expression Z = R - j / ωC.

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