Ngong Agul Manyang
Jul 17
Cylinder drum is 1.8m high and it radius is 0.6m if it total open at end surface area take 3.14?
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ChatGPT
Jul 17
To find the total open end surface area of the cylinder drum, we need to calculate the area of both the top and bottom circles.
The formula for the area of a circle is A = πr^2, where r is the radius of the circle.
Given that the radius of the cylinder drum is 0.6m, we can calculate the area of the top and bottom circles:
A = π(0.6)^2
A = π(0.36)
A = 1.13 m^2
Since there are two end surfaces (top and bottom), the total open end surface area of the cylinder drum is:
Total open end surface area = 2 * 1.13
Total open end surface area = 2.26 m^2
Therefore, the total open end surface area of the cylinder drum is 2.26 square meters.
The formula for the area of a circle is A = πr^2, where r is the radius of the circle.
Given that the radius of the cylinder drum is 0.6m, we can calculate the area of the top and bottom circles:
A = π(0.6)^2
A = π(0.36)
A = 1.13 m^2
Since there are two end surfaces (top and bottom), the total open end surface area of the cylinder drum is:
Total open end surface area = 2 * 1.13
Total open end surface area = 2.26 m^2
Therefore, the total open end surface area of the cylinder drum is 2.26 square meters.
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Google Gemini AI
Jul 17
The total surface area of a cylinder is given by:
$$A = 2\pi r^2 + 2\pi rh$$
where:
- $r$ is the radius of the cylinder
- $h$ is the height of the cylinder
- $\pi$ is a mathematical constant approximately equal to 3.14
In this case, the cylinder has a radius of $r = 0.6$ m and a height of $h = 1.8$ m. Plugging these values into the formula, we get:
$$A = 2\pi (0.6)^2 + 2\pi (0.6)(1.8)$$
$$A = 2\pi (0.36) + 2\pi (1.08)$$
$$A = 0.72\pi + 2.16\pi$$
$$A = 2.88\pi$$
Since $\pi$ is approximately equal to 3.14, the total surface area of the cylinder is approximately:
$$A \approx 2.88 \times 3.14 = 9.0432$$ square meters.
Therefore, the total open surface area of the cylinder is approximately 9.04 square meters.
$$A = 2\pi r^2 + 2\pi rh$$
where:
- $r$ is the radius of the cylinder
- $h$ is the height of the cylinder
- $\pi$ is a mathematical constant approximately equal to 3.14
In this case, the cylinder has a radius of $r = 0.6$ m and a height of $h = 1.8$ m. Plugging these values into the formula, we get:
$$A = 2\pi (0.6)^2 + 2\pi (0.6)(1.8)$$
$$A = 2\pi (0.36) + 2\pi (1.08)$$
$$A = 0.72\pi + 2.16\pi$$
$$A = 2.88\pi$$
Since $\pi$ is approximately equal to 3.14, the total surface area of the cylinder is approximately:
$$A \approx 2.88 \times 3.14 = 9.0432$$ square meters.
Therefore, the total open surface area of the cylinder is approximately 9.04 square meters.
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