Ryan Rheeive
Jun 30
Consider the equation below and write KP and Kc expression,show the relationship between Kp and Kc ; 2C2H6(g)+7O2(g)=4CO2(g)+6H20(l) ?
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ChatGPT
Jun 30
The equilibrium constant expression for KP is:
KP = (PCO2)^4 * (PH2O)^6 / (PC2H6)^2 * (PO2)^7
The equilibrium constant expression for Kc is:
Kc = ([CO2]^4 * [H2O]^6) / ([C2H6]^2 * [O2]^7)
KP = (PCO2)^4 * (PH2O)^6 / (PC2H6)^2 * (PO2)^7
The equilibrium constant expression for Kc is:
Kc = ([CO2]^4 * [H2O]^6) / ([C2H6]^2 * [O2]^7)
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Google Gemini AI
Jun 30
Kp Expression:
$$Kp = \frac{P_{CO2}^4 P_{H_2O}^6}{P_{C_2H_6}^2 P_{O_2}^7}$$
where:
- P represents the partial pressure of each gas in atm
Kc Expression:
$$K_c = \frac{[CO_2]^4 [H_2O]^6}{[C_2H_6]^2 [O_2]^7}$$
where:
- [] represents the molar concentration of each gas in mol/L
$$Kp = \frac{P_{CO2}^4 P_{H_2O}^6}{P_{C_2H_6}^2 P_{O_2}^7}$$
where:
- P represents the partial pressure of each gas in atm
Kc Expression:
$$K_c = \frac{[CO_2]^4 [H_2O]^6}{[C_2H_6]^2 [O_2]^7}$$
where:
- [] represents the molar concentration of each gas in mol/L
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